Updating xml node using vb6

Next(&i) Local Xml Node &name Node = &name Nodes\[&i\]; Local Xml Node &id Attribute = &name Node. Node Value = "New Value"; End-While; Todd: Thanks for the help!

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Is there a method, cause I don’t see in People Books. Thanks, Rich Local array of Xml Node &name Nodes = &in XMLDoc.Get Elements By Tag Name("Name" ); Local integer &i; While &name Nodes. Local array of Xml Node &name Nodes = &in XMLDoc.Next(&i) Local Xml Node &name Node = &name Nodes\[&i\]; Local Xml Node &id Attribute = &name Node. Node Value = "New Value"; End-While; Can you give me a couple lines sample code? How do I get the List Items by Node into an array of nodes that are for that attribute. Get Elements By Tag Name(" Name" ); Local integer &i; While &name Nodes.-- Martin Honnen Microsoft MVP - XML and then simply append a new record using file level I/O.The problem of course is that the above isn't a well-formed XML document because it has no wrapper element.

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